999精品在线视频,手机成人午夜在线视频,久久不卡国产精品无码,中日无码在线观看,成人av手机在线观看,日韩精品亚洲一区中文字幕,亚洲av无码人妻,四虎国产在线观看 ?

GRADIENT ESTIMATE FOR POSITIVE SOLUTIONS OF THE PME UNDER GEOMETRIC FLOW

2021-01-16 09:59:36ZHAOHelei
數(shù)學(xué)雜志 2021年1期

ZHAO He-lei

(School of Mathematics and Statistics,Wuhan University,Wuhan 430072,China)

Abstract:In this paper,we derive a local gradient estimate of the Aronson-B′enilan type with Laplace operator and drifting Laplace operator for positive solutions of porous medium equations posed on Riemainnian manifolds with bounded symmetric tensor by using Li-Yau method.These results extend Zhu Xiao-bao’s and Deng Yi-hua’s results.

Keywords:gradient estimate;geometric flow;porous medium equations;Harnack inequality

1 Introduction

The porous medium equation(PME for short)

appears in the description of different natural phenomena,and its theory and properties depart strongly from the heat equation,ut= ?u,it’s most famous relative.There are kinds of physical applications where we can use this model,mainly to characterize process involving fluid flow,heat transfer or diffusion.For more knowledge,we recommend the book[1]to the reader.

Among typical nonlinear problems,the mathematical theory of PME is also based on a priori estimates.In 1979,Aronson and B′enilan obtained a celebrated second-order differential inequality of the form[2]

which applies to all positive smooth solutions of(1.1)defined on the whole Euclidean space on the condition thatm>mc:=1?2/n.The theory of PME on manifolds is rare.In 2008,Lu,Ni,V′azquez and Villani studied the PME on manifolds[3].They got the following local Aronson-B′enilan estimate.

Assume that Ric≥?(n?1)K2onB(O,R)for someK≥0.Then,for anyα>1,we have that onQ′:=B(O,R/2)×[0,T]

Next,we will discuss PME with drifting Laplacian operator.Smooth metric measure spaces carry a similar operator to the Laplace-Beltrami operator?,thef-Laplacian,which is also called drifting Laplacian or Witten-Laplacian,defined for a functionuby?fu=?u?g(?f,?u)= ?u?〈?f,?v〉.The N-Barkry-Emery Ricci tensor is defined by=Ric+Hessf?df?df.A natural question about smooth metric measure space is which of the results about the Ricci tensor and the Laplace-Beltrami operator can be extended to the N-Bakry-Emery Ricci tensor andf-Laplacian.For example,In[3],Lu et al.derived some gradient estimates for the PME equation on Riemannian manifolds with Ricci curvature bounded from below:

wherem>1.In[4],Huang and Li got a better result in[3].In[5],Huang and Li researched the following porous medium type equation,

on smooth metric measure space.Under the assumption that the N-dimensional Bakery-Emery Ricci curvature is bounded from below,Huang and Li obtained some gradient estimates that generalized the results in[3]and[5].

In this paper,we will follow closely[3]and derive local gradient estimates for positive bounded solutions of PME on Riemannian manifolds under general geometric flow.The general geometric flow equation wherehijis a second-order symmetric tensor is as follows:

The idea is from the Ricci flow=?2Rij,which was introduced by Hamilton[6]in 1982.

Then,we will get a similar result with drifting Laplacian operator on PME.Also,our idea comes from Huang and Ma in[7],who considered gradient estimate for the following parabolic equation

on smooth metric measure spaces.Inspired by the research of harmonic function and positive solution to linear heat flow on Riemannian manifolds,this paper extends corresponding gradient estimate from a fixed Riemannian metric to the case that the metric evolves by a general geometric flow.

Our first result states the gradient estimate of the pressure functionv.

Ciis a constant depending onm,n,a,α,K0,K1,K2,K3,K4,R.

RemarkWhenh=?2Ric,(1.6)is the Ricci flow equation.In this case our results reduce to[8].Note that for Ricci flow the assumption|?Ric|≤K3is not needed because of the contracted second Bianchi identity[[9],section 4].

As an application,we get the following result.

Corollary 1.1vis the pressure,then for anyx1,x2∈B(O,R/6)and anyα>1,

whereγ(s)is a smooth curve connectedx1andx2withγ(t1)=x1andγ(t2)=x2,|γ′(s)|sis the length of the vectorγ′(s)at times.

We extend the Laplacian operator to the drifting Laplacian operator,and we can get similar gradient estimate.

Main Theorem 2Let(Mn,g,dv)be a smooth metric measure space.Suppose thatuis a positive solution to(1.5).If|?f|≤c0,|?2v|≤c1,(Bp(2R))≥?k0,?k1≤h≤k2,|?h|≤k3.Here,k0,k1,k2,k3≥0,then on the ballBp(R)we have

wherec2,c3,c4are constants depending ona,c0,c1,α,m,n,H,R,T,and

Corollary 2.1Let(Mn,g,dv)be a smooth metric measure space with|?f|≤c0,|?2v|≤c1,≥?k0,?k1≤h≤k2,|?h|≤k3.Here,k0,k1,k2,k3≥0 suppose that(Mn,g)is a complete non-compact Riemannian manifold anduis a positive solution to(1.5),then

whereciis a constant depending ona,α,m,n,S,T,andS=

RemarkWhengis independent oft,our results reduce to[10].

2 Proof of Main Theorems

First,let us calculate a formula forL(Fα).

Lemma 2.1

Lemma 2.2 Letg(t)be a solution to the geometric flow on a Riemannian manifoldMn(n≥2)for t in some time interval[0,T].LetMbe complete under the initial metricg(0).Let u be a positive smooth solution to(1.1)on manifold(Mn,g(t))for somem>0,and letv:=be the pressure.Then we have

ProofCalculate directly by using the Lemma 2.1.

Proposition 2.1Letuandvbe as in Lemma 2.2.Then

ProofThe following formula is helpful in the calculation:

Using(2.6)and Lemma 2.2 we have

These give that

Using the formula

we have

Hence we obtain

Note the fourth to eighth terms in the above equation,they can be rewritten as

This completes the proof.

Then,we prove a local estimate for PME on complete manifolds under general geometric flow.We use the technique of Li and Yau[11]and some calculation of Lu,Ni,V′azquez and Villani in[3].Denote byB(O,R)the ball of radiusR>0 and centeredOin(Mn,g(t)),and denote byr(x,t)the distance function fromOtoxwith metricg(t).

Proof of the Main Theorem 1

(i)Since boundedhtensor implies thatg(t)is uniform equivalence to the initial metricg(0)[[12],Corollary 6.11],that ise?2K1Tg(0)≤g(t)≤e2K2Tg(0).By definition,we know that(M,g(t))is also complete fort∈[0,T].Inspired by the choice of cutoff function in the proof of Theorem3.1 in[10],we letη(x,t):=θ(r(x,t)/R)be cutoff function,whereθ(s)is a smooth monotone function which satisfiesθ(s)≡1 for 0≤s≤1/2,θ(s)≡0 fors≥1,and(θ′)2/θ≤40,andθ′′≥?40θ≥?40.OnB(O,R),using the Laplacian comparison theorem,one can easily get

and

(ii)After the preparation in(i),now we applyLtotη(?Fα)and use the maximum principle to obtain our estimates.Iftη(?Fα)≤0 onQ,then the main theorem 1 is trivial.So we assume max(x,t)∈Qtη(?Fα)>0.Supposetη(?Fα)achieves its maximum at(x0,t0).Then we havet0>0 and

at(x0,t0).From now on,all calculations are at(x0,t0).

By the evolution formula of geodesic length under geometric flow(see[13]),we calculate

whereγt0is the geodesic connectingxandOunder the metricg(t0),Sis the unit tangent vector toγt0anddsis the element of arc length.

Here,we have used Proposition 2.1.Using the following inequality,(2.10)and(2.11)

we have

Using Young’s inequality,

and attention our assumption ofh,

On the other hand,

We get

Now writeC3:=80+C1and

Also note that

Using

then the above quadratical inequality(2.12)on(y?αz)reduces to

Proof of the Corollary 1.1Direct calculation implies

The result follows from the observation thatγ(s)lies completely insideB()at any time in[0,T](since bounded tensorhimplies thatg(t)is uniform equivalence to the initial metricg(0))and the estimate in the main theorem 1.

To prove the main theorem 2,we need some lemmas as well.Note

Suppose thatuis a positive solution to(2.13).Letv=.Direct calculation shows that

Since0,then(2.14)is equivalent to

LetL=?t?(m?1)v?fandF=.We have the following lemmas.

Lemma 2.3Suppose thatuis a poistive solution to(2.13).Then

ProofDirect calculation shows that

Therefore,we get

and

By(2.15)and Lemma 2.1,we have

According to(2.18),(2.19),(2.20),and(2.21).We conclude that

On the other hand,by(2.14)we get

Direct calculation shows that

According to(2.23)and(2.24),we obtain

According to[[14],[15]],we have

By(2.25)and(2.26),we conclude that(2.17)is true.

Lemma 2.4The functionFsatisfies the following equation:

ProofFor the reader’s convenience,we give the details of the proof of Lemma 2.4.By(2.16)and(2.17),we have

By the definition of F,we have

According to(2.15)we get

Using(2.15)again,we arrive at

Putting(2.29),(2.30)and(2.31)into(2.28),we conclude that(2.27)is true.

By(2.15)and definition ofF,we get

Putting(2.33)into(2.32),we obtain

Attention the definition ofh,|?f|,the following reality and the Young’s inequality,

we have,

where we have used?ax2+bx≤b2/4ato the first term in the second inequality.

According to(2.4)and(2.5)in[7],we can construct a cut-off functionφsuch that 0≤φ≤1,sup(φ)?Bp(2R),φ|Bp(R)=1 and

whereCis a constant depending only on n.SetG=tφα?1F.Assume thatGachieves its maximum at the point(x0,s)∈Bp(2R)×[0,T]and assumeG(x0,s)≥0.By the maximum principle,we have

at the point(x0,s),and

Multiplying both sides of(2.36)bysφ,and using?ax2+bx≤b2/4a,we get

inequality becomes

We can get

Hence,for allx∈Bp(R),it holds that

Thus,the proof of the main theorem 2 is completed.LettingR→∞,c4→,we get the result of Corollary 1.2.

主站蜘蛛池模板: 乱系列中文字幕在线视频 | 欧美日韩资源| 国产在线小视频| 亚洲欧美色中文字幕| 欧美性精品不卡在线观看| 99视频全部免费| 亚洲精品另类| 欧美成人亚洲综合精品欧美激情| 欧美高清国产| 成人一级免费视频| 搞黄网站免费观看| 中文字幕久久亚洲一区| 老司机精品一区在线视频| 国产理论精品| 精品三级在线| h视频在线播放| 亚洲高清无码久久久| 亚洲男人的天堂视频| 国产精品区视频中文字幕| 亚洲二区视频| 91黄色在线观看| 国产一区二区影院| 欧美成人区| 久久久噜噜噜久久中文字幕色伊伊 | 激情亚洲天堂| 高清精品美女在线播放| 91精品福利自产拍在线观看| 99久久国产综合精品2020| 国产免费怡红院视频| 欧美日韩第三页| 亚洲浓毛av| 91探花国产综合在线精品| 成年看免费观看视频拍拍| 综合五月天网| 伊人大杳蕉中文无码| 亚洲综合九九| 99热这里只有精品在线观看| 久久精品66| 国产99视频在线| 精品国产自在在线在线观看| 国产乱子伦无码精品小说| 四虎在线观看视频高清无码| 亚洲男女在线| 久久免费视频6| 国产成人一级| 成人一级免费视频| 欧美日韩成人| 天天综合网站| 国产哺乳奶水91在线播放| 精品人妻AV区| 四虎成人免费毛片| 亚洲成aⅴ人在线观看| 欧美精品影院| 尤物精品国产福利网站| 亚洲嫩模喷白浆| 成人久久精品一区二区三区| 精品福利一区二区免费视频| 伊人久久精品无码麻豆精品| 人妻夜夜爽天天爽| 精品一区国产精品| 色综合久久无码网| 99在线观看国产| 伊人色天堂| 亚洲一区二区三区国产精华液| 天天色天天综合| 日本日韩欧美| 国产爽妇精品| 国产成在线观看免费视频| 国产精品妖精视频| 国产精品理论片| 日韩无码真实干出血视频| 成人日韩视频| 久草网视频在线| 亚洲精品天堂自在久久77| 婷婷久久综合九色综合88| 久久精品无码一区二区国产区| 成人国产小视频| 毛片基地视频| 亚洲第一色视频| 欧美在线观看不卡| 久久免费视频播放| 97久久免费视频|