智破貪污案

1. Baboon， a famous detective， is good at maths. This helps him a lot. 狒狒探長是遠近聞名的偵探，在數學方面有很深的造詣，這對破案很有幫助。

2. Mr Panda， the accountant in the Peach Village， finds 100 yuan missing. And two numbers on the bill are stained as 52.7 by ink. Mr Panda asks the handler—the golden vulture why. 話說桃樹村的會計熊貓先生結帳時發現缺了一百元，經反復查對原始單據，發現一張單據中有兩個數字被墨水污染成52.7元。會計找來此單據的經手人——金雕詢問倩況。

3. “The numbers are one. The money is 152.71 yuan. 72 people buy peaches. They bought the same number of peaches and gave me the same amount of money. I gave them receipt but it was stained as this.”金雕說：“被污染的數字都是l。這筆款是152.71元。我只記得有72個人來買桃子，每人買的桃子同樣多，每人交的錢同樣多。我給他們集體寫了張收款單，不小心污染成這樣子。”

4. People checked the money and still 100 yuan is missing. The village committee asks Mr Panda to come. 按金雕說的原始單據的錢數進行核算，仍短一百多元。村委會請來了狒狒探長。

5. Hearing about it， Baboo understands. “The money is 252.72 yuan. You get 100.01 yuan.” 探長聽了匯報，心中有數了。探長對金雕說：“這筆款應是252.72元，是你貪污了一百元零一分。”

6. The detective tells the reasoning. The golden vulture has to admit. 探長講出推理過程，金雕只好老實交待。

Keys： 被污染的兩個數用□代替，是□52.7□元=□527□分。72人每人交的錢數相同，那么□527□的倍數。因為72=8×9，所以□527□既能被8整除，又能被9整除。□527□中三個已知數字的和是5+2+7=14。如 保持被9整除，兩個□中數字之和應為4‘因為該數能被8整除，所以個位上的數應是偶數（0、2、4）。因為最高位不能是0，所以個位上的數是0或2。又因 為實際短缺一百多元，所以個位和最高位上的數都是2。這筆款是25272分=252.72元。